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Question

Add (6ab35ab)(2a2+b5), ab(a2+1) and ab3(3a3+2b+1).

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Solution

Given that,

(6ab35ab)(2a2+b5)+ab(a2+1)+ab3(3a3+2b+1)

=12a3b3+6ab430ab310a2b5ab225ab+a3b+ab+3a4b3+2ab4+ab3

=12a3b3+8ab429ab310a2b5ab22ab+a3b+3a4b3

=3a3b3(4+a)5ab(2a+b)+ab3(8b29)+ab(a22)

Hence, this is the answer.


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