Question

# Add the following: $a-b+ab,b-c+bc,c-a+ac$

Open in App
Solution

## To add : $a-b+ab,b-c+bc,c-a+ac$On combining the like terms and adding them we get$=\left(a–b+ab\right)+\left(b–c+bc\right)+\left(c–a+ac\right)\phantom{\rule{0ex}{0ex}}=a–b+ab+b–c+bc+c–a+ac\phantom{\rule{0ex}{0ex}}=a–a+b–b+c–c+ab+bc+ca\phantom{\rule{0ex}{0ex}}=0+0+0+ab+bc+ca\phantom{\rule{0ex}{0ex}}=ab+bc+ca$Hence, On adding $a-b+ab,b-c+bc,c-a+ac$ we get $ab+bc+ca$.

Suggest Corrections
0
Explore more