Additive inverse of $10$ is

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- 10

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Solution

The correct option is B $- 10$
Let additive inverse of $10$ be $x$ .
$10 + x = 0$

$∴ x = - 10$

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Similar questions

The additive inverse of an integer x is given by -x.

Therefore, the additive inverse of -10 is -(-10) = 10

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(\frac{- 7}{15}) + 0 = \frac{- 7}{15} = 0 + (\frac{- 7}{15})

\frac{2}{5} + (\frac{- 2}{5}) = 0

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