Question

# Aditya has built a cubical water tank with lid for his house with each outer edge equal to $1.5\mathrm{m}$. He gets the outer surface of the tank including the base, covered with square tiles of side $25\mathrm{cm}$. Find how much he would spend on tiles if the cost of tile is $₹480$ per dozen?

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Solution

## Step 1: Find the surface area of tank and one tileWe have,Edge of the tank$=1.5\mathrm{m}=150\mathrm{cm}\left[\because 1\mathrm{m}=100\mathrm{cm}\right]$Cost of $12$ tiles$=₹480$Then,Surface area of the tank$=5×{\left(\mathrm{side}\right)}^{2}$ $=5×{\left(150\right)}^{2}\phantom{\rule{0ex}{0ex}}=5×150×150{\mathrm{cm}}^{2}$Area of each tile $={\left(\mathrm{side}\right)}^{2}$ $=25×25{\mathrm{cm}}^{2}$Step 2: Find the number of tilesTherefore, number of tiles required$=\frac{\mathrm{Surface}\mathrm{area}\mathrm{of}\mathrm{tank}}{\mathrm{Area}\mathrm{of}1\mathrm{tile}}$ $=\frac{5×150×150}{25×25}\phantom{\rule{0ex}{0ex}}=180\mathrm{tiles}$Step 3: Find the total cost of tilesWe know that, Cost of $12$ tiles$=₹480$Cost of $1$ tile$=\frac{480}{12}=₹40$Therefore, cost of $180$ tiles$=40×180=₹7200$Hence, the required answer is $₹7200$ .

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