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Question

Aforce of 1200 newton acts on surface of area 10 cm square, normally what would be the pressure applied on the surface?


Solution

given force= F = 1200 N
Area = A =10 cm² = 10 space cross times 10 to the power of negative 4 end exponent space m squaredequals 10 to the power of negative 3 end exponent space m squared

pressure = fraction numerator F o r c e over denominator A r e a end fraction =F over A=1200 over 10 to the power of negative 3 end exponent equals 1200 cross times 10 cubed equals 12 cross times 10 to the power of 5 pascal

bar is also unit of pressure  where 1 pascal equal to 10 to the power of negative 5 end exponent bar
so , 12 cross times 10 to the power of 5 pascal = 12 bar

Physics

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