Question

# After the capacitor gets fully charged, S1 is opened and S2 is closed so that the inductor is connected in series with the capacitor. Then,

A
at t=0, energy stored in the circuit is purely in the form of magnetic energy
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B
at any time t>0, current in the circuit is in the same
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C
at t>0, there is no exchange of energy between the inductor and capacitor
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D
at any time t>0, instantaneous current in the circuit may vCL
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Solution

## The correct option is D at any time t>0, instantaneous current in the circuit may v√CLEnergy stored in the circuit at t=0 is magnetic as well as electrostatic(12CV2). Current in the circuit is not the sameFor t>0Q=Q0sin(ωt+δ)dQdt=i=Q0ωcos(ωt+δ)i=CV×1√CL as ωt+δ=0i=V√CL

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