All edges of a square pyramid are of equal lengths. If the length of the base edge is $40 c m$ , what is the slant height?

1200

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1600

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$20 \sqrt{3}$

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$10 \sqrt{3}$

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Solution

The correct option is C
$20 \sqrt{3}$

Note that Base edge = Lateral side = $40 c m$

Slant height = $\sqrt{(L a t e r a l e d g e)^{2} - (H a l f t h e b a s e e d g e)^{2}}$

Slant height = $\sqrt{(40)^{2} - (20)^{2}} = 20 \sqrt{3}$

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All edges of a square pyramid are of equal lengths. If the length of the base edge is 40 cm, what is the slant height?

The correct option is C 20√3 Note that Base edge = Lateral side = 40 cm Slant height = √(Lateral edge)2−(Half the base edge)2 Slant height = √(40)2−(20)2=20√3

All edges of a square pyramid are of equal lengths. If the length of the base edge is $40 c m$ , what is the slant height?

The correct option is C
$20 \sqrt{3}$

Note that Base edge = Lateral side = $40 c m$

Slant height = $\sqrt{(L a t e r a l e d g e)^{2} - (H a l f t h e b a s e e d g e)^{2}}$

Slant height = $\sqrt{(40)^{2} - (20)^{2}} = 20 \sqrt{3}$