All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick the incorrect option.

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Solution

The correct option is A
If velocity versus time graph is a straight line with negative slope, then acceleration is constant and negative.
With a negative slope, distance-time graph will be parabolic $(s = u t - 1 / 2 a t^{2})$
So, option (d) will be incorrect.

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All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.

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