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Question

Aluminium hydroxide is soluble in excess of NaOH forming the ion :

A
AlO23+
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B
AlO23
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C
AlO2
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D
AlO3
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Solution

The correct option is C AlO2

Alluminium hydroxide reacts with excess of NaOH and forms AlO2.

Al(OH)3+NaOHNaAlO2+2H2O

So the NaAlO2 forms AlO2.

Hence option C is correct.

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