Question

# Amit walks $$16\ m$$ south from his house and turns east to walk $$63\ m$$ to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance he walk while returning?

Solution

## It is given thatAmit walks $$16\ m$$ south from his house and turns east to walk $$63\ m$$ to reach his friend's houseConsider $$O$$ as the house and $$A$$ and $$B$$ as the palces$$OA=16\ m, OA=63\ m$$Using Pythagoras theorem$$OB^{2}=OA^{2}+AB^{2}$$Substituting the values $$=16^{2}+63^{2}$$By further calculation$$=256+3969$$$$=4225$$So we get$$OB=\surd 4225=65$$Maths

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