Amit walks $16 m$ south from his house and turns east to walk $63 m$ to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance he walk while returning?

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Solution

It is given that
Amit walks $16 m$ south from his house and turns east to walk $63 m$ to reach his friend's house
Consider $O$ as the house and $A$ and $B$ as the palces
$O A = 16 m, O A = 63 m$
Using Pythagoras theorem
$O B^{2} = O A^{2} + A B^{2}$
Substituting the values
$= 16^{2} + 63^{2}$
By further calculation
$= 256 + 3969$
$= 4225$
So we get
$O B = \sqrt 4225 = 65$

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Amit walks 16 m south from his house and turns east to walk 63 m to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance he walk while returning?

It is given thatAmit walks 16 m south from his house and turns east to walk 63 m to reach his friend's houseConsider O as the house and A and B as the palcesOA=16 m,OA=63 mUsing Pythagoras theoremOB2=OA2+AB2Substituting the values =162+632By further calculation=256+3969=4225So we getOB=√4225=65

Amit walks $16 m$ south from his house and turns east to walk $63 m$ to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance he walk while returning?