Ammoniacal solution of $M g S O_{4}$ in presence of $N H_{4} C I$ is heated with $N a_{2} H P O_{4}$ a white crystalline precipitate is formed of

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Solution

The correct option is A
$M g^{2 +} + N H_{3} + H P O_{4}^{2 -} \to M g (N H_{4}) P O_{4}$

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Similar questions

$M g S O_{4}$ on reaction with $N H_{4} O H$ and $N a_{2} H P O_{4}$ forms a white crystalline precipitate. What is its formula?

M g S O_{4} + N H_{4} O H + N a_{2} H P O_{4} \to

M g S O_{4}

N H_{4} C l

N a_{3} P O_{4}

M g S O_{4}

N H_{4} O H

N a_{2} H P O_{4}

N H_{4} O H

N H_{4} C l

A l_{2} (S O_{4})_{3}

M g S O_{4}

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