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Question

Among H2, H+2, Li2, Be2, B2, C2, O2,, N2, andF2 the number of diamagnetic species are: (Atomic numbers: H=1,He=2,Li=3,Be=4,B=5,C=6,N=7,O=8,F=9)

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Solution

Molecular orbitals configurations-
H21sσ2
H+21sσ1
Be21sσ21sσ22sσ22sσ2
Li21sσ21sσ22sσ2
B21sσ21sσ22sσ22sσ2(2pxπ1=2pyπ1)
C21sσ21sσ22sσ22sσ2(2pxπ2=2pyπ2)
N21sσ21sσ22sσ22sσ2(2pxπ2=2pyπ2)2pzσ2
O21sσ21sσ22sσ22sσ22pzσ2(2pxπ2=2pyπ2)(2pxπ1=2pyπ0)
F21sσ21sσ22sσ22sσ22pzσ2(2pxπ2=2pyπ2)(2pxπ2=2pyπ2)

Diamagnetic speciesall electrons paired
H2, Li2, Be2, C2, N2 and F2 are diamagnetic species.

However, the bond order of Be2 is zero thus Be2 does not exist. So, the number of diamagnetic species is 5.

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