Question

Among $\left[Ni\right(CO{)}_4],[Ni(CN{)}_4{]}^{2-}$ and $[NiC{l}_4{]}^{2-}$ species, the hybridisation state of $Ni$ atoms are respectively:

• A. $s{p}^3,d{s}^{2}p,ds{p}^2$
• B. $s{p}^3,ds{p}^2,s{p}^3$
• C. $s{p}^3,s{p}^3,ds{p}^2$
• D. $ds{p}^2,s{p}^3,s{p}^3$

Answer 1

The correct option is B $s{p}^3,ds{p}^2,s{p}^3$

As $C{N}^{-}$ is a strong ligand so here pairing happens and $ds{p}^2$ hybridisation (square planar) takes place while $\left[Ni\right(CO{)}_4]$ and $[NiC{l}_4{]}^{2-}$ have $s{p}^3$ hybridisation (tetrahedral shape).

Hence, the correct option is $B.$