Among the following the compounds which one is both paramagnetic and coloured?

K_{2} C r_{2} O_{7}

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(N H_{4})_{2} [T i C l_{6}]

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V O S O_{4}

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K_{3} [C u (C N)_{4}]

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Solution

The correct option is B $V O S O_{4}$
In $K_{2} C r_{2} O_{7}$ , the $C r$ is in +6 oxidation state.

Electronic configuration of $C r^{+ 6} = 3 d^{0}$

In $(N H_{4})_{2} [T i C l_{6}],$ the $T i$ is in $+ 4$ oxidation state.

Electronic configuration of $T i^{+ 4} = 3 d^{0}$

In $V O S O_{4}$ , $V$ is in $+ 4$ oxidation state.

Electronic configuration of $V^{+ 4} = 3 d^{1}$

It contains 1 unpaired electron.

$K_{3} [C u (C N)_{4}] \to C u^{+} : 3 d^{10}$

$V O S O_{4}$ , due to the presence of one unpaired electron, is paramagnetic and coloured.

Hence, option C is the answer.

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