Among the following, the number of compounds that can react with $P C l_{5}$ to give $P O C l_{3}$ is:___
$O_{2}, C O_{2}, S O_{2}, H_{2} O, H_{2} S O_{4}, P_{4} O_{10}$ .

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Solution

$P C l_{5}$ produces $P O C l_{3}$ with the following reagents
$P C l_{5} + S O_{2} \to P O C l_{3} + S O C l_{3}$
$P C l_{5} + H_{2} O \to P O C l_{3} + 2 H C l$
$2 P C l_{5} + H_{2} S O_{4} \to S O_{2} C l_{2} + 2 P O C l_{3} + 2 H C l$
$6 P C l_{5} + P_{4} O_{10} \to 10 P O C l_{3}$

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