Among the following, the number of compounds that can react with $P C l_{5}$ to give $P O C l_{3}$ is:
$C_{2} H_{5} O H, S O_{2}, H_{2} O, H_{2} S O_{4}, P_{4} O_{10}$

Open in App

Solution

$C_{2} H_{5} O H + P C l_{5} \to C_{2} H_{5} C l + P O C l_{3} + H C l$
$S O_{2} + P C l_{5} \to S O C l_{2} + P O C l_{3}$
$H_{2} O + P C l_{5} \to P O C l_{3} + 2 H C l$
$H_{2} S O_{4} + P C l_{5} \to P O C l_{3} + H S O_{3} C l + H C l$
$P_{4} O_{10} + 6 P C l_{5} \to 10 P O C l_{3}$

Suggest Corrections

Similar questions

P C l_{5}

P O C l_{3}

O_{2}, C O_{2}, S O_{2}, H_{2} O, H_{2} S O_{4}, P_{4} O_{10}

P C l_{5}

P O C l_{3}

P C l_{5}

P O C l_{3}

0.450

P_{4} O_{10}

P C l_{5}

6 P C l_{5} + P_{4} O_{10} \to 10 P O C l_{3}

P O C l_{3}

P C l_{5}