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Question

Among the following which one has the highest paramagnetism?


  1. [Cr(H2O)6]3+

  2. [Fe(H2O)6]2+

  3. [Cu(H2O)6]2+

  4. [Zn(H2O)6]2+

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Solution

The correct option is B

[Fe(H2O)6]2+


The explanation for the correct option

(B) [Fe(H2O)6]2+

Paramagnetism

  • Paramagnetism is the ability of certain materials to be weakly attracted to the magnetic field.
  • Paramagnetism is exhibited by molecules containing unpaired electrons.
  • The paramagnetism property of a complex increases with the larger number of unpaired electrons.

  • The electronic configuration of Fe2+ is Ar3d6
  • H2O is a weak field ligand it does not pair up unpaired electrons.
  • The number of unpaired electrons in [Fe(H2O)6]2+ is 4
  • As the number of unpaired electrons is higher, the paramagnetic property of the complex is also higher.

Hence Option (B) [Fe(H2O)6]2+is correct

The explanation for the incorrect options

(A) [Cr(H2O)6]3+

  • The electronic configuration of Cr3+ is Ar3d3
  • H2O is a weak field ligand it does not pair up unpaired electrons.
  • The number of unpaired electrons in [Cr(H2O)6]3+ is 3
  • As the number of unpaired electrons is lower the paramagnetism property of the complex is also lower.

(C) [Cu(H2O)6]2+

  • The electronic configuration of Cu2+ is Ar3d9
  • H2O is a weak field ligand it does not pair up unpaired electrons.
  • The number of unpaired electrons in [Cu(H2O)6]2+ is 1
  • As the number of unpaired electrons is lower the paramagnetism property of the complex is also lower.

(D) [Zn(H2O)6]2+

  • The electronic configuration of Zn2+ is Ar3d10
  • H2O is a weak field ligand it does not pair up unpaired electrons.
  • The number of unpaired electrons in [Zn(H2O)6]2+ is 0
  • There are no unpaired electrons. Hence this complex is diamagnetic

Therefore, Option (B) [Fe(H2O)6]2+ is correct


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