Among the halides, the order of decreasing lewis acid character is:
$1. B C l_{3}, 2. A l C l_{3}, 3. G a C l_{3}, 4. I n C l_{3}$

1 > 2 > 3 > 4

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4 > 2 > 3 > 1

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2 > 1 > 3 > 4

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1 < 2 < 3 < 4

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Solution

The correct option is A $1 > 2 > 3 > 4$
The monomeric trihalides being electron deficient, are strong lewis acids.

Among the halides.
$1. B C l_{3}, 2. A l C l_{3}, 3. G a C l_{3}, 4. I n C l_{3}$
The order of decreasing Lewis acid character is $B C l_{3} > A l C l_{3} > G a C l_{3} > I n C l_{3} .$ as on moving down the boron family the lewis acid character decreases.
Hence the correct option is $1 > 2 > 3 > 4$
$I n {C l}_{3} i s t h e s t r o n g e s t l e w i s a c i d a n d {B C l}_{3} i s t h e l e a s t s t r o n g e s t b e c a u s e i n {B C l}_{3} t h e 2 p π = 3 p π b a c k b o n d i n g i s t h e s t r o n g e s t, h e n c e i t i s m u c h m o r e s t a b l e a n d h e n c e a w e a k e r l e w i s a c i d$ $F o r f o r m i n g b a c k b o n d i n g o n e o f t h e b o n d e d a t o m s s h o u l d b e f r o m s e c o n d p e r i o d a n d t h e a t o m s a c c e p t i n g e l e c t r o n s s h o u l d h a v e e m p t y o r b i t a l .$

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1. B C l_{3}, 2 . A l C l_{3}, 3 . G a C l_{3}, 4 . In C l_{3}

i . B C l_{3}

i i . A l C l_{3}

i i i . G a C l_{3}

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