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Question
A
motor car is going due north at a speed of 50 km/h. It makes a 90 left turn
without changing the speed. The change in the velocity of the car is about:
A
motor car is going due north at a speed of 50 km/h. It makes a 90 left turn
without changing the speed. The change in the velocity of the car is about:
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Solution
The correct option is B 70 km/h towards south- west
Initial velocity = vi=50jFInal velocity =vf=−50iChange in velocity = Δv=vf−vi=−50i−50j Negative x- means west direction and negative y-component means south direction. Hence resultant velocity is in south-west direction.Magnitude of change in velocity = √(−502)+(−502)) = 70. 71 km/h
Initial velocity = vi=50j
FInal velocity =vf=−50i
Change in velocity = Δv=vf−vi=−50i−50j
Negative x- means west direction and negative y-component means south direction. Hence resultant velocity is in south-west direction.
Magnitude of change in velocity = √(−502)+(−502)) = 70. 71 km/h
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