Amperes circuital law is given by

\oint ¯ H . ¯ d l = μ_{0} I_{e n c}

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\oint ¯ B . ¯ d l = μ_{0} I

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\oint ¯ B . ¯ d l = μ_{0} J

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\oint ¯ H . ¯ d l = μ_{0} J

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Solution

The correct option is C $\oint ¯ B . ¯ d l = μ_{0} I$
Ampere 's circuital law states that relationship between thecurrent and the magnetic field
$ϕ \to B \to d l = μ_{0} I$
B is correct option

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i = 3 sin ω t + 4 cos ω t

_{1},_{2}

_{3}

I_{1}, I_{2}

I_{3}

\oint \to B . \to d l = μ_{0} I

\to B

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