Question

An AC generator consists of a coil of 2000 turns each of area 80 $c{m}^2$ and rotating at an angular speed of 200 rpm in a uniform magnetic field of $4.8\times {10}^{-2}T$. Calculate the peak of emf in the coil.

Answer 1

from given,

the number of turns in the coil(N) = 2000

area(A) = 80${cm}^2$ =80$\times {10}^{-4}{m}^2$

$\omega =200rpm=\frac{200}{60}=\frac{20}{6}rps$

magnetic field = $4.8\times {10}^{-2}$Tesla

peak or maximum value of emf = NBA $\omega$

=$2000\times 4.8\times {10}^{-2}\times 80\times {10}^{-4}\times \frac{20}{6}$

=$256\times {10}^{-2}$ Volts