Question

An AC source has a rms value of voltage of $\frac{200}{\sqrt{2}}$. The value of voltage after $\frac{1}{600}$ s from the start when frequency is 50 Hz is

• A. 200 V
• B. $\frac{200}{\sqrt{2}}$
• C. 100 V
• D. 50 V

Answer 1

Answer: (C)

100 V

$V_{rms}=\frac{200}{\sqrt{2}}V$
$V_0=\sqrt{2}{V}_{rms}=\sqrt{2}\times \frac{200}{\sqrt{2}}$ = 200 V

$and,$
$V=V_{0}sin2\pi vt=200sin(2\pi \times 50\times \frac{1}{600})$
$=200sin\frac{\pi }{6}=200\times \frac{1}{2}=100V$