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Question

An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3Ω, the phase difference between the applied voltage and the current in the circuit is

A
π/6
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B
π/4
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C
π/2
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D
Zero
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Solution

The correct option is B π/4

ϕ=tan1(XLR)=tan1(33)=tan1(1)=π4rad


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