Question

An AC voltage source has an output of $\Delta V=\left(200V\right)\sin 2\pi ft$. This source is connected to a $100\Omega$ resistor. RMS current in the resistance is

• A. $1.41A$
• B. $2.41A$
• C. $3.41A$
• D. $0.71A$

Answer 1

Answer: (A)

$1.41A$

On comparing the given source voltage with $V=V_o\sin wt$

We get, $V_o=200$ volts

Rms voltage of source $V_{rms}=\frac{V_o}{\sqrt{2}}=\frac{200}{\sqrt{2}}=100\sqrt{2}$ volts

Thus rms current $I_{rms}=\frac{V_{rms}}{R}$ where $R=100\Omega$

$⟹$ $I_{rms}=\frac{100\sqrt{2}}{100}=\sqrt{2}=1.41A$