Question

An aeroplane flies 400 m North and 300 m South and then flies 1200 m upwards then net displacement is

• A. 1204.15 m
• B. 1300 m
• C. 1400 m
• D. 1500 m

Answer 1

Answer: (A)

1204.15 m

R.E.F image

$AB=400m$

$BC=300m$

$CD=1200m$

$AC=100m$

$AD=\sqrt{(AC{)}^2+(CD{)}^2}=\sqrt{(100{)}^2+(1200{)}^2}$

$AD=\sqrt{1450000}$

$AD=1204.15946$ $\theta =ta{n}^{-1}\left(12\right)$