An aeroplane is flying at a height of 1960 m in horizontal direction with a velocity of 360 km/hr. When it is vertically above the point. A on the ground, it drops a bomb. The bomb strikes a point B on the ground, then the time taken by the bomb to reach the ground is

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Solution

The correct option is B
$t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 1960}{9.8}} = 20 s e c$

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