Question

# An aeroplane is flying in a horizontal direction with a velocity 600 km/h at  height of 1960 m. When it is vertically above the point A on the ground, a body is dropped from it. The body strikes the ground at point B. Calculate the distance AB.

Solution

## From $$\displaystyle h= \frac{1}{2}gt^{2}$$we have $$\displaystyle t_{OB}= \sqrt{\frac{2h_{OA}}{g}}= \sqrt{\frac{2\times 1960}{9.8}}= 20 s$$Horizontal distance $$\displaystyle AB= vt_{OB}$$$$\displaystyle = \left ( 600\times \frac{5}{18}m/s \right )\left ( 20s \right )$$$$\displaystyle = 3333.33m= 3.33 km$$Physics

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