Question

# An aeroplane is flying in a horizontal direction with a velocity $$600kmh^{-1}$$ at a height of $$1960$$m. When it is vertically above the point  A on the ground, a body is dropped from it. The body strikes the ground at point B. Calculate the distance AB.

A
3.33km
B
333km
C
33.3km
D
3330km

Solution

## The correct option is A $$3.33$$kmWhen the body is dropped it will have an initial horizontal velocity which is equal to speed of the aeroplane. So the bomb fall and travel forward too.Initial horizontal velocity $$v_x=600km/hr$$$$\Rightarrow v_x=600km/hr=600\times \dfrac{5}{18}m/s$$                                    $$=166.67m/s$$Initial vertical velocity $$v_y=0$$Height $$h=1960$$Time taken to fall $$=t$$$$\Rightarrow h=v_yt+\dfrac{1}{2}8t^2$$$$\Rightarrow 1960=0+\dfrac{1}{2}\times 9.8\times t^2$$$$\Rightarrow 1960=4.9t^2$$$$\Rightarrow t^2=\dfrac{1960}{4.9}=400$$$$\Rightarrow t=205$$In $$20s,$$ the horizontal distance travelled is AB.$$\Rightarrow AB=v_xt=166.67\times 20=3333.4m$$Hence, the answer is $$3333.4m.$$Physics

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