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Question

An aeroplane moving with 150 m/s drops a bomb from a height of 80 m so as to hit a target. What is the distance between the target and the point where the bomb is dropped? (given g = 10 m/s2)


A

605.3 m

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B

600 m

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C

80 m

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D

230 m

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Solution

The correct option is A

605.3 m


The horizontal distance covered by bomb,
BC =vH × 2hg= 1502 × 8010 = 600 m


The distance of target from dropping point
The distance of target from dropping point of bomb,
AC = AB2+BC2 = (80)2+(600)2 = 605.3 m


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