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Question

An aircraft has 120 passenger seats. The number of seats occupied during 100 flights is given in the following table.
Number of seats100104104108108112112116116120Frequency1520321815
Determine the mean number of seats occupied over the flights.


Solution

We first, find the class mark xi of each class and then proceed as follows.
Number of seats & Class marks(xi)Frequency(fi)Deviation di=xiafidi10010410215812010410810620480108112a=110320011211611418472116120118158120N=fi=100fidi=8Assumed mean,a=110,
Class width, h = 4
and total observation, N = 100
By assumed mean method, 
Mean (¯x)=a+fidifi=110+(8100)=1100.08=109.92

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