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Question

An aircraft moving with a speed of 540 km/h is at a height of 6000 m, just overhead of an anti aircraft gun. If the muzzle velocity of the bullet is 300 m/s, the firing angle Q from the horizontal for the bullet to hit the aircraft should be


A
30
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B
45
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C
60
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D
37
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Solution

The correct option is C 60
Let bullet hits the aircraft in time t.
Displacment of aircraft in time t= horizontal displacement of projectile
Given vaircraft=540×518=150 m/s
Horizontal velocity of bullet
(vbullet)x=V0×cosQ=300cosQ
Since horizontal motion of bullet is non accelerated,
150×t=300cosQ×t
cos Q=150300=12
Q=60

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