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Question

An alloy of copper, silver and gold is found to have copper constituting the (FCC) lattice. If silver atoms occupy the edge centres and gold is present at body centre, the alloy has a formula

A
Cu4Ag2Au
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B
Cu4Ag4Au
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C
Cu4Ag3Au
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D
CuAgAu
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Solution

The correct option is D Cu4Ag3Au
Number of Cu atoms in the fcc unit cell =8×18+6×12=4
Ag atoms occupying the edge centres =12×14=3
Au atoms present at the body centre =1
Hence, the ratio of Cu:Ag:Au=4:3:1. Therefore, the formula is Cu4Ag3Au.

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