Question

An alternating voltage given by V = 140 sin 314t is connected across a pure resistor of 50 $\Omega$, the rms current through the resistor is

• A. 1.98 A
• B. 5.63 A
• C. 8.43 A
• D. 2.39 A

Answer 1

Answer: (A)

1.98 A

Here $R=50\Omega ,V_0=140V$

$I_{rms}=\frac{V_{rms}}{R}$

$=0.707\times \frac{V_o}{R}$

$=0.707\times \frac{140}{50}$

$=1.98A$