Balancing Chemical Equations by Partial Equation Method
An amount of ...
Question
An amount of a mole of calcium cyanamide and 1 mole of water are allowed to react. The number of moles of ammonia produced is
A
3.0
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B
2.0
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C
1.0
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D
0.67
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Solution
The correct option is C0.67 CaCH2+3H2O→CaCO3+2NH3 1/3 mole +1 mole from 2/3 mole 1 mole calcium cyanomide react with 3 mole of water to form 2 mole ammonia. ∴ Given 1 mole CaCN2+1 mole water ∴1 mole of water with 13 mole of CaCH2 to give 23 mole CaCN2 ∴ remain unreacted nNH3=23=0.67