An analyser is inclined to a polarizer at an angle of 30o. the intensity of light emerging from the analyser is 1nth of that is incident on the polarizer. Then n is equal to
A
4
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B
43
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C
83
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D
14
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Solution
The correct option is C83
Given,
θ=300
Lets consider I0= Intensity of incident light
Intensity of light passing though the analyser is given by