Question

# An ant moves along the square loop of side a m. If it moves along path ABC, starting from A to reach at the point C in 2 s. The average velocity of ant will beAvergae velocity of ant is a m/s along ABCAvergae velocity of ant is a√2 m/s along ACAvergae velocity of ant is 3a√2 m/s along BCAverage velocity of ant is zero.

Solution

## The correct option is B Avergae velocity of ant is a√2 m/s along ACThe displacement of ant will be the length of diagonal AC. ΔS=AC=√2 a m Δt=2 s velocityavg=ΔSΔt ∴velocityavg=√2a m2 s=a√2 m/s This is the required magnitude of average velocity. However, the direction of average velocity will be along the direction of displacement(A→C). ⇒ Avergae velocity of ant is a√2 m/s along AC

Suggest corrections