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Question

An aqueous solution is prepared by diluting 3.30 mL of acetone (density = 0.789 g/mL) to get the final volume of 75 mL. Find the mole fraction of acetone. (Assume no volume change on mixing).

A
0.11
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B
0.1
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C
0.001
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D
0.01
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Solution

The correct option is D 0.01
We know that:
Density=MassVolume
Mass of acetone=volume×density=3.30 mL×0.789 g mL1=2.603 g

Number of moles of acetone in the solution =2.603 g58 g mol1=0.044 mol
Mass of water=(Final volumeinitial volume)×density of water

We know that density of water is 1.00 g/mL

Mass of water=(75.00 mL3.30 mL)×1 g mL1=71.70 g

Number of moles of water =71.718.0=3.98 mol

We know that:
Molefraction=number of moles of speciestotal number of moles

Mole fraction of acetone=0.0440.044+3.98=0.010

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