An aqueous solution of $F e S O_{4}, A l_{2} (S O_{4})_{3}$ and chrome alum is heated with excess of $N a_{2} O_{2}$ and filtered. The materials obtained are:

a colourless filtrate and a green residue

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a yellow filtrate and a green residue

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a yellow filtrate and a brown residue

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a green filtrate and a brown residue

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Solution

The correct option is C a yellow filtrate and a brown residue
Both $A l^{3 +}$ and $C r^{3 +}$ goes into solution as $[A l (O H)_{4}]^{-}$ and $C r O_{4}^{2 -}$ (yellow solution). $F e^{2 +}$ is precipitated as $F e (O H)_{2}$ . In air, $F e (O H)_{2}$ is converted into $F e (O H)_{3}$ (brown residue).

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Q. An aqueous solution of

F e S O_{4} A l_{2} (S O_{4})_{3}

and chromium alum is heated with excess of

N a_{2} O_{2}

and filtered. The material obtained is :

Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
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With H

_{2}

S, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H).

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An aqueous solution of FeSO4,Al2(SO4)3 and chrome alum is heated with excess of Na2O2 and filtered. The materials obtained are:

The correct option is C a yellow filtrate and a brown residueBoth Al3+ and Cr3+ goes into solution as [Al(OH)4]− and CrO2−4 (yellow solution). Fe2+ is precipitated as Fe(OH)2. In air, Fe(OH)2 is converted into Fe(OH)3 (brown residue).

An aqueous solution of $F e S O_{4}, A l_{2} (S O_{4})_{3}$ and chrome alum is heated with excess of $N a_{2} O_{2}$ and filtered. The materials obtained are: