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Question
An army contingent of 616 member is to March behind an army band of 32 members in A parade the two groups are to March in the same number of columns what is the maximum number of columns in which they can march
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Solution
No of Army Contingent Members= 616
No of members in Army Bands= 32
Situation Given---> Columns should be equal and maximum in number.
The situation can be found out by finding the HCF of number 616 and 32 .
By Euclid's division lemma,
616=32*19+8
32=8*4+0
Since remainder equal 0 at this step . HCF of 616 and 32 is 8.
Required Answer--> The maximum number of columns in which they can march is 8 columns.
No of Army Contingent Members= 616
No of members in Army Bands= 32
Situation Given---> Columns should be equal and maximum in number.
The situation can be found out by finding the HCF of number 616 and 32 .
By Euclid's division lemma,
616=32*19+8
32=8*4+0
Since remainder equal 0 at this step . HCF of 616 and 32 is 8.
Required Answer--> The maximum number of columns in which they can march is 8 columns.
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