Question

# An artificial satellite revolves around the earth in a circular orbit with a speed $$v$$. If $$m$$ is the mass of the satellite, its total energy is.

A
12mv2
B
12mv2
C
mv2
D
32mv2

Solution

## The correct option is B $$-\frac{1}{2}mv^2$$Kinetic energy of satellite, $$KE=\displaystyle\frac{1}{2}mv^2$$where $$v=\sqrt{\dfrac{GM}{r}}$$Potential energy of satellite, $$PE=\displaystyle\frac{-GMm}{r}=-mv^2$$$$\therefore$$ Total energy $$=KE+PE$$$$=\displaystyle\frac{1}{2}mv^2-mv^2$$$$=-\displaystyle\frac{1}{2}mv^2$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More