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Question

An artificial satellite revolves around the earth in a circular orbit with a speed $$v$$. If $$m$$ is the mass of the satellite, its total energy is.


A
12mv2
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B
12mv2
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C
mv2
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D
32mv2
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Solution

The correct option is B $$-\frac{1}{2}mv^2$$
Kinetic energy of satellite, $$KE=\displaystyle\frac{1}{2}mv^2$$
where $$v=\sqrt{\dfrac{GM}{r}}$$
Potential energy of satellite, $$PE=\displaystyle\frac{-GMm}{r}=-mv^2$$
$$\therefore$$ Total energy $$=KE+PE$$
$$=\displaystyle\frac{1}{2}mv^2-mv^2$$
$$=-\displaystyle\frac{1}{2}mv^2$$

Physics

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