Question

# An artificial satellite revolves around the earth in a circular orbit with a speed $$v$$. If $$m$$ is the mass of the satellite, its total energy is :

A
12mv2
B
12mv2
C
mv2
D
32mv2

Solution

## The correct option is D $$-\dfrac { 1 }{ 2 } m{ v }^{ 2 }$$Kinetic energy of satellite, $$KE = \dfrac { 1 }{ 2 } m{ v }^{ 2 }$$where $$v = \sqrt { \dfrac { GM }{ r } }$$Potential energy of satellite,$$PE = \dfrac { -GMm }{ r } = -m{ v }^{ 2 }$$$$\therefore$$ Total energy $$= KE + PE$$                      $$=\dfrac { 1 }{ 2 } m{ v }^{ 2 } - m{ v }^{ 2 } = -\dfrac { 1 }{ 2 } m{ v }^{ 2 }$$Physics

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