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Wavelength

An astronomic...

Question

An astronomical telescope has an angular magnification of magnitude $5$ for distant objects. The separation between the objective and the eye-piece is $36 c m s$ and the final image is formed at infinity. The focal length $f_{0}$ of the objective and $f_{e}$ of the eye piece are

f_{0} = 45 c m

and

f_{e} = - 9 c m

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f_{0} = 7.2 c m

and

f_{e} = 5 c m

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f_{0} = 50 c m

and

f_{e} = 10 c m

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f_{0} = 30 c m

and

f_{e} = 6 c m

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Solution

The correct options are
A $f_{0} = 45 c m$ and $f_{e} = - 9 c m$
D $f_{0} = 30 c m$ and $f_{e} = 6 c m$
$M = \frac{f_{0}}{f_{e}} = 5$

$L = f_{0} + f_{e} = 36$

$∴ f_{e} = 6 c m, f_{0} = 30 c m$

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