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Electronic Configuration

An atom of an...

Question

An atom of an element contains $29$ electrons and $35$ neutrons.
Deduce (i) the number of protons and (ii) the electronic configuration of the element.

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Solution

The number of protons is equal to the number of electrons which is $29$ .
It also corresponds to the atomic number.
The electronic configuration of the element will be $[A r]^{18} 3 d^{10} 4 s^{1}$ .

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Q. The atom of an element X contains 17 protons, 17 electrons and 18 neutrons whereas the atom of an element Y contains 11 protons, 11 electrons and 12 neutrons.

(a) What type of ion will be formed by an atom of element X ? Write the symbol of ion formed.
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(c) What type of ion will be formed by an atom of element Y ? Write the symbol of ion formed.
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Q. Write electronic configuration of element

_{17}^{35} T

State number of protons and neutrons in

T

Q. Question 6
Which of the following are true for an element?
(i) Atomic number = number of protons + number of electrons
(ii) Mass number = number of protons + number of neutrons
(iii) Atomic number = number of protons = number of neutrons
(iv) Atomic number = number of protons = number of electrons

(a) (i) and (ii)
(b) (i) and (iii)
(c) (ii) and (iii)
(d) (ii) and (iv)

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