An electric bulb is designed to operate at $12$ volts $D C .$ If this bulb is connected to an $A C$ source and gives normal brightness, what would be the peak voltage of the source?

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Solution

Step 1: Given data.
Voltage $= 12 V$
Step 2: Solve for the peak value of voltage.
The rms value of the AC voltage must be equal to $12 V$
The peak value of the voltage is
$= \sqrt{2} \times 12 V = 16.8 V$
Thus, the peak voltage is $= 16.85 V$

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An electric bulb is designed to operate at 12volts DC. If this bulb is connected to anAC source and gives normal brightness, what would be the peak voltage of the source?

Step 1: Given data.Voltage =12VStep 2: Solve for the peak value of voltage.The rms value of the AC voltage must be equal to 12VThe peak value of the voltage is =2×12V=16.8VThus, the peak voltage is =16.85V

An electric bulb is designed to operate at $12$ volts $D C .$ If this bulb is connected to an $A C$ source and gives normal brightness, what would be the peak voltage of the source?

Step 1: Given data.
Voltage $= 12 V$
Step 2: Solve for the peak value of voltage.
The rms value of the AC voltage must be equal to $12 V$
The peak value of the voltage is
$= \sqrt{2} \times 12 V = 16.8 V$
Thus, the peak voltage is $= 16.85 V$