Question

An electric bulb is designed to operate at 12 volts DC. If this bulb is connected to an AC source and gives normal brightness , what would be the peak voltage of the source?

Answer 1

We have,

Potential $=12v$

So, The rms value of the AC voltage must be equal to $12v$.

Thus, The peak value of the voltage is:

$=\sqrt{2}\times 12v$

$=16.85v$

Thus, the peak voltage of the source is$=16.85v$