An electric charge q exert a force F on a similarly electric charge q separated by a distance r- A third charge q4 is placed midway between the two charges- Now the force between the previous two charges-

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Standard XII

Physics

Gauss's Law

An electric c...

Question

An electric charge q exert a force $F$ on a similarly electric charge $q$ separated by a distance $r .$ A third charge $\frac{q}{4}$ is placed midway between the two charges. Now the force between the previous two charges.

\frac{F}{3}

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\frac{F}{9}

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Zero

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F

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Solution

The correct option is B $\frac{F}{9}$
Electric charge $= q$
Force $= F$
charge $e = q$ by a distance $= r$
third charge $= \frac{q}{4}$
$F = \frac{1}{4 π ϵ_{0}} \frac{q \times \frac{q}{4}}{r^{2}}$
$= K \frac{q^{2}}{{4 r}^{2}}$
$F^{1} = \frac{F}{9}$

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An electric charge q exert a force F on a similarly electric charge q separated by a distance r. A third charge q4 is placed midway between the two charges. Now the force between the previous two charges.

The correct option is B F9Electric charge =qForce =Fcharge e=q by a distance =rthird charge =q4F=14πϵ0q×q4r2 =Kq24r2F1=F9

An electric charge q exert a force $F$ on a similarly electric charge $q$ separated by a distance $r .$ A third charge $\frac{q}{4}$ is placed midway between the two charges. Now the force between the previous two charges.

The correct option is B $\frac{F}{9}$
Electric charge $= q$
Force $= F$
charge $e = q$ by a distance $= r$
third charge $= \frac{q}{4}$
$F = \frac{1}{4 π ϵ_{0}} \frac{q \times \frac{q}{4}}{r^{2}}$
$= K \frac{q^{2}}{{4 r}^{2}}$
$F^{1} = \frac{F}{9}$