An electric dipole has the magnitude of its charge as $q$ and its dipole moment is $p$ . It is placed in uniform electric field $E$ . If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively

q . E

and max

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2 q . E

and min.

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q . E

and min

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zero and min.

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Solution

The correct option is D zero and min.
When the dipole is in the direction of field then net force is $q E + (- q E) = 0$
and its potential energy is minimum $= - p . E$
$= - q a E$

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An electric dipole has the magnitude of its charge as q and its dipole moment is p. It is placed in uniform electric field E. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively

The correct option is D zero and min.When the dipole is in the direction of field then net force is qE+(−qE)=0and its potential energy is minimum =−p.E=−qaE

An electric dipole has the magnitude of its charge as $q$ and its dipole moment is $p$ . It is placed in uniform electric field $E$ . If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively

The correct option is D zero and min.
When the dipole is in the direction of field then net force is $q E + (- q E) = 0$
and its potential energy is minimum $= - p . E$
$= - q a E$