Question

# An electric dipole of moment 'p' is placed in an electric field of intensity 'E'. The dipole acquires a position such that the axis of the dipole makes an angle 0 with the direction of the field. Assuming that the potential energy of the dipole to be zero when $$\theta = 90^0$$, the torque and the potential energy of the dipole will respectively be:

A
pEsinθ,2pEcosθ
B
pEcosθ,pEsinθ
C
pEsinθ,pEcosθ
D
pEsinθ,2pEcosθ

Solution

## The correct option is C $$pE \, sin \theta, - pE\, cos \,\theta$$Potential energy of the dipole$$U=-\int { T } dB$$    $$=-\int _{ \pi /2 }^{ \theta }{ PE\sin\theta } d\theta$$    $$=PE\left( \cos\theta -0 \right) =-PE\cos\theta$$and potential energy $$=PE\sin\theta$$.Physics

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