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Question

# An electric discharge is passed through a mixture containing 50 cc of O2 and 50 cc of H2. The volume of the gases formed (i) at room temperature, (ii) at 110C will be:

A
(i) 25 cc (ii) 50 cc
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B
(i) 50 cc (ii) 75 cc
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C
(i) 25 cc (ii) 75 cc
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D
(i) 75 cc (ii) 75 cc
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Solution

## The correct option is B (i) 25 cc (ii) 75 cc2H2(g)+O2(g)→2H2O 50 cc H2 will combine with 25 cc O2 to form 50 cc H2O∴O2 left = 25 cc At room temperature, H2O will be in liquid state but at 110oC, it will be gaseous. Thus, volume of gases at 25C and 110oCwill be 25 cc and 75 cc respectively.

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