An electric heater draws a current of 4 A and its element has a resistance of 40 - If heater is switched on for 8 minutes- calculate the energy released in kilojoules-

Current i = 4 A Resistance R = 40 Ω time t= 8×60 second #160;Heat generated H= i^2Rt = 16× 40× 8× 60 J =16× 40× 8× 601000 kJ ...

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Standard X

Physics

Heating Effect of Current

An electric h...

Question

An electric heater draws a current of $4 A$ and its element has a resistance of $40 Ω$ . If heater is switched on for $8 m i n u t e s$ , calculate the energy released in kilojoules.

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Solution

Current $i = 4 A$
Resistance $R = 40 Ω$
time $t = 8 \times 60 s e c o n d$
Heat generated $H = i^{2} R t$
= $16 \times 40 \times 8 \times 60 J$
$= \frac{16 \times 40 \times 8 \times 60}{1000} k J$
= $307.2 k J$

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An electric heater draws a current of 4 A and its element has a resistance of 40 Ω. If heater is switched on for 8 minutes, calculate the energy released in kilojoules.

Current i=4 AResistance R=40 Ωtime t=8×60 second Heat generated H=i2Rt=16×40×8×60 J=16×40×8×601000 kJ= 307.2 kJ

An electric heater draws a current of $4 A$ and its element has a resistance of $40 Ω$ . If heater is switched on for $8 m i n u t e s$ , calculate the energy released in kilojoules.

Current $i = 4 A$
Resistance $R = 40 Ω$
time $t = 8 \times 60 s e c o n d$
Heat generated $H = i^{2} R t$
= $16 \times 40 \times 8 \times 60 J$
$= \frac{16 \times 40 \times 8 \times 60}{1000} k J$
= $307.2 k J$